Write a slope-intercept equation for a line passing through the point (5,-4) that is perpendicular to the line 5x+6y=7

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 5x + 6y = 7 into this form

subtract 5x from both sides

6y = - 5x + 7 ( divide all terms by 6 )

y = - x + ← in slope-intercept form

with slope m = -

given a line with slope m then the slope of a line perpendicular to it is

= - , hence

= - 1 / - =

y = x + c ← is the partial equation

to find c substitute (5, - 4 ) into the partial equation

- 4 = 6 + c ⇒ c = - 4 - 6 = - 10

y = x - 10 ← equation in slope-intercept form

-4

step-by-step explanation:

(-4+8)=-(4-8)=-8+4=-4

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol