How do i set up this problem?

Hey there!

We know that perimeter is all the sides added up.

70= 2w+2L <== this is the basic equation

We know that the rectangles length is three times as long as it is wide.

So, you know that is is three times the length of the width. So, put 3 times w in as length and times that by two since there are two length sides, and keep width the same. 2w because there are two width sides. Then, solve.

70=2(3w)+2w

70= 6w+2w

70=8w

w=8.75

We can check this by plugging it in to our first equation and seeing if it works. First, we need to multiply 8.75 by 3 to get the value for length.

8.75*3= 26.25

2(26.25)+2(8.75)= 70 <=== it works!

So, the length is 26.25 cm and the width is 8.75 cm.

I hope this helps!

~kaikers

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: