Aline passes through the points (-4,5) and (4,1). find the slope ? what is the y-intercept of the equation? write the equation of the line of the above points. shown all work below . you so much if you actually answer this question with a good explaination along with work shown.

Hey there!

Use the slope formula.

m= (y2-y1)/(x2-x1)

Plug in the points. (-4,5) and (4,1)

m= (1-5)/(4-(-4)

m= -4/4+4

m=-4/8

m=-1/2

To find the y-intercept, first plug it into the the point slope. You just need one set of points for this, I will use (4,1)

y-y1=m(x-x1)

y-1= -1/2(x-4)

y-1=-1/2x+2

Add 1 to the other side.

y= -1/2x+3

The 3 is your y-intercept. It is in slope intercept form now. (y=mx+b) The b is the y-intercept.

The equation of the line is usually represented by the slope intercept form, which you already have: y=-1/2x+3.

I hope this helps!

~kaikers

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

answer: i believe the answer is e

step-by-step explanation: