Mathematics, 30.06.2019 22:30 2Thea12Maine6
(05.03 mc) the figure below shows a square abcd and an equilateral triangle dpc: abcd is a square. p is a point inside the square. straight lines join points a and p, b and p, d and p, and c and p. triangle d ted makes the chart shown below to prove that triangle apd is congruent to triangle bpc: statements justifications in triangles apd and bpc; dp = pc sides of equilateral triangle dpc are equal in triangles apd and bpc; ad = bc sides of square abcd are equal angle adc = angle bcd = 90° so angle adp = angle bcp = 30° triangles apd and bpc are congruent sas postulate which of the following completes ted's proof? (1 point) in square abcd; angle adc = angle bcd in square abcd; angle adp = angle bcp in triangles apd and bpc; angle adp = angle bcp
Answers: 1
Mathematics, 21.06.2019 18:30, waldruphope3956
Can someone check if i did this right since i really want to make sure it’s correct. if you do you so much
Answers: 2
Mathematics, 21.06.2019 21:00, taylordalton93
Factor the trinomial below. 12x^2 - 32x - 12 a. 4(3x+3)(x-1) b. 4(3x+1)(x-3) c. 4(3x+6)(x-2) d. 4(3x+2)(x-6)
Answers: 2
(05.03 mc) the figure below shows a square abcd and an equilateral triangle dpc: abcd is a square....
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