Find the equation of the line parallel to 5x-2y=2 that passes through point (-4,-3)

A very quick way of solving this problem is to recognize and use the fact that a line parallel to 5x-2y=2 has an equation which is exactly the same as 5x-2y=2 except for the constant.

Replace that 2 (on the right side of the equation) with C, and x with -4, and y with -3:

5(-4)-2(-3)=C

and find C.  C = -20 + 6 = -14.

Therefore, the equation of the line parallel to 5x-2y=2 passing thru the point (-4, -3) is 5x-2y= -14.  Notice how only the constant changes.

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation:

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.