Ajuggler tosses a ball into the air . the balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40t+4 . suppose the juggler missed and ball hit the ground . find the maximum height of the ball and time it took to reach the ground. round all answers to the nearest hundredth .

Maximum height is 29 ft

Time to reach the ground is 2.60 seconds

Step-by-step explanation:

We are given equation of height as

Maximum height:

we know that at maximum height

velocity =0

so, we will find derivative

and then we can set it to 0

and we solve for t

now, we can set it to 0

and then we can solve for t

now, we can plug t into height equation

Time to reach the ground:

we know that at ground

height=0

so, we can set h(t)=0

and then we can solve for t

we can use quadratic formula

Since, time can never be negative

so, we will only consider positive time

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6

1/800 is the right answer