Argyle cut a 300-meter cable into two pieces. one piece was 15m longer than twice the length of the other. find the length of the longer piece.

205 m

let x be the length of one piece then the other piece is 2x + 15

The sum of the 2 pieces equals 300 m , hence

x + 2x + 15 = 300

3x + 15 = 300 ( subtract 15 from both sides )

3x = 285 ( divide both sides by 3 )

x = 95

length of longer piece = (2 × 95 ) + 15 = 190 + 15 = 205 m

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.