Mr. mole and bugs bunny started digging their way into the ground from different locations at the same time. they each dug at a constant rate. the following equation gives mr. mole's altitude (in meters relative to the ground) as a function of time (in minutes). a =-4-0.6ta=−4−0.6t bugs bunny's altitude (in meters relative to the ground) as a function of time (in minutes) is given by the following table of values: \text{time}time (minutes) \text{altitude}altitude (meters) 22 -1.6−1.6 99 -7.2−7.2 1616 -12.8−12.8 who dug faster?

mr mole because just showing that mr mole dag the fasest

Bug Bunny dig faster.

Step-by-step explanation:

Mr.  Mole--

We are given a function that represents the altitude (in meters relative to the ground) as a function of time (in minutes) as:

Hence, the rate at which Mr. Mole dig is: -0.6

Bugs Bunny--

Time (minutes)     Altitude (meters)

   2                                 2

 -1.6                             −1.6

   9                                 9

 -7.2                            −7.2

   16                                16

  -12.8                         −12.8

This means the function could be represented as:

Hence, the rate at which Bug Bunny dig is: 1

Hence, as the rate at which Bug Bunny dig is faster than Mr. Mole.

Hence, Bug Bunny dig faster.

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