Afootball team won 8 more games than they lost. they played 24 games in the season. how many games were won and how many were lost?

The team lost n games.

The team won 8 more games than it lost, so it won n + 8.

The total number of games the team played was n + n + 8, or 2n + 8.

The team played a total of 24 games, so

2n + 8 = 24

We now solve for n.

2n + 8 = 24

2n = 16

n = 8 (lost games)

n + 8 = 8 + 8 = 16 (won games)

The team won 16 games and lost 8 games.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.