Which of the following pairs of functions are inverses of each other?

one way is to solve for the invers of the first function

remembe, to solve, replace f(x) or g(x) with y, switch x and y, solve for y and replace it with f⁻¹(x)

A.

f(x)=x/2+8

y=x/2+8

x=y/2+8

x-8=y/2

2x-16=y

f⁻¹(x)=2x-16

nope, not A

B.

f(x)=3x³+16

y=3x³+16

x=3y³+16

x-16=3y³

(x-16)/3=y³

∛((x-16)/3)=y

f⁻¹(x)=∛((x-16)/3)

nope, not the same

not B

C.

f(x)=18/x-9

y=18/x-9

x=18/y-9

x+9=18/y

y(x+9)=18

y=18/(x+9)

f⁻¹(x)=18/(x+9)

correct, the answer is C

answer is C

2 is the final ! : )

really really sorry if i'm

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