71. which equation represents a line that is parallel to y= -2x + 1 and that passes through the point (-4, 3)? a. y= -2x -1 b. y= -2x -5 c. y= 1/2x -1 d. y= 1/2x -5

For lines to be parallel, they have to have the SAME slope.

The given line's slope is -2, so the parallel line's slope is also -2.

You will be using the equation:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0)

Since you know the slope, you can plug it in.

y = mx + b

y = -2x + b

To find "b", you can plug in the point (-4, 3) into the equation.

y = -2x + b

3 = -2(-4) + b

3 = 8 + b

-5 = b

Your equation is:

y = -2x - 5

Your answer is B

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.