Which polynomial is a product of (3x+2) and (x-7)

(3x+2)  (x-7)

FOIL

first 3x*x  = 3x^2

outer  3x*-7 = -21x

inner = 2*x = 2x

last  2*-7 = -14

add them together  = 3x^2 -21x+2x -14

combine like terms  3x^2 -19x -14

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

answer: 1 and 3

step-by-step explanation: