If h(x)= -kx + 14 and h(2)=18, find the value of k

h(x)= -kx + 14

18 = -k*2 + 14   since x=2

18 = -2k +14

subtract 14 from each side

4 = -2k

divide by -2

-2 =k

k = - 2

evaluate h(2), equate to 18 and solve for k

h(2) = - 2k + 14 = 18 ( subtract 14 from both sides )

- 2k = 4 ( divide both sides by - 2 )

k = - 2

its d. the first coordintaes are 10,32

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !