The vertex of a parabola is at point 2,5.which equations could be for this parabola below? ? a.)y=(x-2)^2-5 b.)x=-4(y-2)^2 c.)y=(x+5)^2+2 d.)y=(x+2)^2-5

The vertex form of the equation of a vertical parabola is

y = (x-h)^2 + k, where (h,k) is the vertex.

Here, because the vertex is at (2,5), that equation must be:

y = (x-2)^2 + 5.

Answer A is closest, but ought to be A) y = (x-2)^2 + 5 (the 5 is positive).

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew