What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3? what are the solutions of this equation? 47 m 2 + 88 m + 39 = 0

Hi!

For f(x) = 2x^2 – 10x – 3, the zeros for this quadratic are:

For f(m) = 47m^2 – 88m + 33 = 0, the solutions for this equation are:

Step-by-step explanation:

Having a quadratic function: ax^2 + bx + c = 0, the values of x which are the solutions of the equation are given by the quadratic formula.

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

5x+10 is the correct one

hope this