Name two numbers if one is 3more than twice another and their sum is 57

Let one number = x

Let the other = y

2x + 3 = y              (1)

 x + y = 57            (2)

work with the top equation get the y on the left and the 3 on the right

2x + 3 = y                 Subtract 3 from both sides.

2x + 3 - 3 = y - 3      Combine

2x = y - 3                 Subtract y from both sides.

2x - y = y - y - 3       Combine on the right

2x - y = - 3              (3)   Add (3) and (2) together.

x + y = 57

3x = 54                    Divide by 3

3x/3 = 54/3             Do the division

x = 18  

Find y

x + y = 57                 Substitute for x

18 + y = 57               Subtract 18

18 - 18 + y = 57 - 18  Combine

y = 39

Answer

x = 18

y = 39

answer: options?

step-by-step explanation:

i think 1: 2

step-by-step explanation: