Aprojectile is shot into the air following the path h(x)= 3x^2 -12x + 5. at what time value x will it reach a maximum height ? a. x=1 b. x= 2 c. x= 4 d. x= 5 and explain

The maximum or minimum occurs when x is at the axis of symmetry

it will be a maximum since h(x) opens upward (a>0)

to find the axis of symmetry

h= -b/2a    (ax^2 +bx+c)    so b=-12  and a=3

h = -(-12)/2(3) = 12/6 = 2

x=2

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says