Given: ∆akl, ak = 9 m∠k = 90° m∠a = 60° find: p∆akl the area of ∆akl

Given: In triangle AKL,  AK = 9 units,    

In triangle AKL

Sum of interior angles of the triangle is 180 degree;

or

Substitute the given values we get;

Now, in a 30°-60°-90° triangle, the length of the hypotenuse is twice the length of the shorter leg, and the length of the longer leg is times the length of the shorter leg.

Length of shorter leg (AK) = 9 units

From the above definition:

⇒ units

and

⇒ units.

To find the perimeter of ∆AKL;

Perimeter(P) is the sum of all the sides of a triangle.

⇒

Substitute the given values we get;

units.

Now, to find the area of triangle AKL;

Substitute the given values we get;

square units

Therefore, the perimeter of ∆AKL is, units anmd area of triangle is, square units