Assume that a procedure yields a geometric distribution where the probability of success is 63%. use the geometric probability formula to find the probability that the first success occurs after the sixth trial. 0.003 0.014 0.055 0.125

Option A - 0.003

Step-by-step explanation:

Given: Probability of success = 63%= 0.63  

Probability of failure = 1-0.63=0.37

To find: Probability that the first success occurs after the sixth trial

Formula for calculating geometric probabilities:  

If P(X >n)  or the probability that it takes more than a certain number of trials to achieve the first success.

where, X has a geometric distribution,p is the probability of success and (1-p) is the failure and possible values of X are 1, 2, 3, ....  

Now, put values p=0.63, (1-p)= 0.37 , n=6 in the formula  

Therefore, Option A is correct

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72