When quinn got home, he turned the air conditioner on. t(t)t(t)t, left parenthesis, t, right parenthesis models the temperature in quinn's home (in degrees celsius) after ttt minutes. t(t)=42-0.7tt(t)=42? 0.7tt, left parenthesis, t, right parenthesis, equals, 42, minus, 0, point, 7, t how fast did the temperature drop?

Answer is 0.7 degrees celcius per minute

Explanation:

given that T(t) = 42-0.7t

We have to find the rate of drop of temperature.

For that we find drop of T in 1 minute

Consider T(t) for t minutes and t+1 minutes

T(t+1) = 42-0.7(t+1)

T(t) = 42-0.7t

Difference i.e. drop in temperature in one minute

= T(t+1)-T(t)

= 42-0.7(t+1)-(42-0.7t)   =-0.7

Hence drop per minute = 0.7 degree celcius.

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)