Abusiness rents in-line skates and bicycles. during one day, the business has a total of 26 rentals and collects $485 for the rentals. if in-line skates are rented for $10 per day and bicycles are rented for $35 per day, find the number of pairs of stakes rented and the number of bicycles rented.

A business rents in-line skates and bicycles.

During one day the business has a total of 26 rentals and;

Collects $485 for the rentals.

In-line skates are rented for $10 per day and;

Bicycles are rented for $35 per day.

Solution:

Let the number of in-line skates rented be x and;

The number of bicycles rented be y.

x + y = 26 ... (i)

10x + 35y = 485 ... (ii)

This forms a system of linear equations (i) and (ii)

Solving this system by elimination;

We multiply (i) by 10 and (ii) by 1

10x + 10y = 260 ... (i)

10x +35y = 485 ... (ii)

Subtracting (ii) - (i) gives;

25y = 225 , y = 225/25 = 9

x = 26 - 9 = 17

The number of in-line skates rented were 17.

The number of bicycles rented were 9.

slope is 35 and 20 miles is the y-intercept.

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116