The standard form of the equation of a parabola is x=y^2+10y+22 what is the vertex for of the equation

Complete the square of y^2 + 10y to answer this question.

x=y^2 + 10y + 22 becomes x = y^2 + 10y + 25 - 25 + 22,  or

x = (y+5)^2 - 3

Comparing this result to the generic form x = a(y-k)^2 + h, we see that

h = -5 and k = -3.

Then the vertex of this parabola is at (-5, -3).

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

∡ eia and ∡ kij are congruent

step-by-step explanation: