A5-digit combination lock with digits 0-9 can be opened only if a correct combination of digits is chosen. find the probability of guessing the correct combination if: a. no digit is repeated a0 a1 b. digits can repeat and zero is not one of the digits in the combination a2 a3

The total number of combinations without restrictions is

10 * 10 * 10 * 10 * 10 = 100000

Problem A

10 * 9 * 8 * 7 * 6  = 30240

the number of ways the combination can be set up with no repetition.

The probability of such an event is P = 30240 / 100000 = 0.3024

Problem B

The number of ways that can be done with repetition and no zeros is

9 * 9 * 9 * 9 * 9 = 59049

The probability of such an event is

P = 59049 / 100000 = 0.59049

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: