What is the recursive formula for 3,7,11,

Arithmetic sequence: a_n=a_1+(n-1)d where: d = common difference between terms; n = term; a_1 = first term of sequence a_n = 3+(n-1)4 = 3+(4n-4) = 4n-1 Therefore, a_50 = 4(50)-1 = 200 - 1 = 199

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.