Which is the equation in point-slope form of the line that contains points a and e?

y+2 = 3/4(x+4)

or with the other point

y-4 = 3/4 (x-4)

Step-by-step explanation:

We can find the slope of the line since we have 2 points

A(-4,-2) and E(4,4)

m = (y2-y1)/(x2-x1)

    = (4--2)/(4--4)

   = (4+2)/(4+4)

   =6/8

   = 3/4

Then we can use point slope form

y-y1 = m(x-x1)

y--2 = 3/4 (x--4)

y+2 = 3/4(x+4)

or with the other point

y-4 = 3/4 (x-4)

Point-slope form:  

Step-by-step explanation:

We are given some points on coordinate plane.

We need to find the equation of line in point slope form which passes through A and E

First we write the coordinate of point A and Point E

Point A: (-4,-2)

Point E:  (4,4)

Formula:

where,

Hence, The slope point form of line is

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

6.5

step-by-step explanation:

you said it was in the question

~courtney