What is the equation of the line in slope-intercept form? line on a coordinate plane. the line runs through points begin ordered pair negative 2 comma 0 end ordered pair and begin ordered pair 0 comma 5 end ordered pair.

Find the equation of the line connecting (0, 5) and (-2, 0).

As we go from the first point to the second, x decreases by 2 and y decreases by 5.  Thus, the slope of this line is m = rise / run = -5/(-2), or 5/2.

Starting with the general equation of a line in slope-intercept form, y = mx + b, substitute the knowns as appropriate to determine the value of b:

y= mx + b => 5 = (5/2)(0) + b.  Then b = 5, and the desired equation is

y = (5/2)x + 5.

Check this!  If we subst. the coordinates of (-2,0) into this equation, is the equation true?

0 = (5/2)(-2) + 5

Yes.  So, y = (5/2)x + 5 is the desired equation.

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !

10 - 8 = -2

  8 - 6 = -2

etc, so -2 is the common difference

step-by-step explanation: