Acompany is producing a candy bar with an average weight of 58 grams and a standard deviation of 2 grams. to pass inspection and be boxed to sell, the company has stated that the weight of an individual bar must fall within the middle 99.7% of all the candy bar weights. assuming the weights are normally distributed and with the mean in the middle, plot a line segment that represents the range of weights that will pass inspection.

Z score table

15% from 100% is 99.85

99.85% represents 2.96 Standard deviation from mean

so ₊₋ 2.96 represent the middle 99.7%  of all candy bars weight

2.96 ×  2 gm / SD = 5.92

so acceptable weight would be :-   58 + - 5.92 =   52.08gm  and 63.92gm

so line would be :-     52.08gm                                63.92gm

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.

what are the options? ?

step-by-step explanation: