What is the equation of the line that is perpendicular to a line with a slope of 2, and intersects that line at (4,2)? y=−2x+10 y=−1/2x+4 y=−1/2x−4 y=2x−6

The equation would be y = -1/2x + 4

Step-by-step explanation:

In order to find the equation of the line, we first need to look at the slope. Perpendicular lines have opposite and reciprocal slopes. Since the original slope was 2, we know the perpendicular slope would be -1/2. Now we can use this and a point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 2 = -1/2(x - 4)

y - 2 = -1/2x + 2

y = -1/2x + 4

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .