In a parallelogram efgh, ej=x^2-4 and jg=3x. what is eg?

EG = 24 ( solution is attached below)

Answer : The value of side EG is, 24 units.

Step-by-step explanation :

Property of parallelogram:

The diagonals bisect each other and the opposite sides are equal to each other.

In the given parallelogram EFGH,

Given:

Side EJ =

Side JG = 3x

According to the property of parallelogram,

Side EJ = Side JG

(x-4) = 0  and  (x+1) = 0

x = 4  and x = -1

Now we have to determine the value of side EG.

Side EG = Side EJ + Side JG

Side EG =

Now put the value of x = 4, we get:

Side EG =

Now put the value of x = -1, we get:

Side EG =

As we know that, the value of side can not be negative. So, the value of side EG will be, 24 units.

Hence, the value of side EG is, 24 units.

60: 45 =12: 9 =4: 3 so the answer is 4: 3

alright so i think for this one it would to draw it out. this may be hard for me to try and draw, but i will do my best on here:

        r

  /       |     \

notice how it forms 2 triangles inside one bigger triangle.

so if we know the angle spr is the same as psr that is saying the measure of angle p is the same as angle s. this means the big triangle psr is either isosceles or equilateral. in both cases, the triangle is perfectly symmetrical when split down the middle, which is in this case rq. because we know it is perfectly symmetrical on both sides, we know that the two triangles inside the bigger one are equal.