Abakery sells 5800 muffins in 2010. the bakery sells 7420 muffins in 2015. write a linear model that represents the number y of muffins that the bakery sells x years after 2010. the linear model is y= .

points (0 ,5800)

    ( 5,7420)

slope = (y2-y1)/(x2-x1)

   = (7420-5800)/(5-0)  =1620/5=324

point slope form =

y -y1 = m(x-x1)

y-5800 = 324(x-0)

y-5800 = 324x

y = 324x+5800

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )