In △abc, point m is the midpoint of ab , point d is the midpoint of cm , and abmd=3 cm2. find acdb, aamc, aabd, aadc, and aabc. plz do it asap you don't need to show work just give the !

The area of triangle CDB is 3 cm². The area of triangle AMC is 6 cm². The area of triangle ABD is 6 cm². The area of triangle ADC is 3 cm². The area of triangle ABC is 12 cm².

Explanation:

It is given that in △ABC, point M is the midpoint of AB , point D is the midpoint of CM , and area of BMD=3 cm².

The median is divide the area of the triangle in two equal parts.

Since M is the midpoint of AB, therefore MC is the median and the area of triangle AMC and area of triangle BMC are equal.

  .... (1)

It is given that the point D is the midpoint of CM, therefore BD is the median and the area of BMD is equal to the area of CBD.

Since the area of BMD is 3 cm².

Therefore, the area of triangle CBD is 3 cm².

From equation (1).

Therefore, the area of triangle AMC is 6 cm².

It is given that the point D is the midpoint of CM, therefore AD is the median and the area of AMD is equal to the area of ADC.

  .... (2)

Since M is the midpoint of AB therefore area of AMD and BMD are same and the area of BMD is 3 cm².

.

Therefore the area of triangle ADC is 3 cm².

Therefore the area of triangle ABD is 6 cm².

Therefore the area of triangle ABC is 12 cm².

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

sorry, i can't understand your question. will later if you describe more clearly!

: )