Ashipment of sugar fills 2 4/5 containers. if each container holds 3 2/7 tons of sugar, what is the amount of sugar in the entire shipment? write your answer as a mixed number in simplest form.

total sugar=number of containters filled times sugar per container

convert each to a/b form to multiply easier since

2 4/5=2+4/5=(2*5)/5+4/5=10/5+4/5=14/5

3 2/7=3+2/7=(3*7)/7+2/7=21/7+2/7=23/7

total sugar=number of containers times sugar per container

total sugar=2 4/5 times 3 2/7

total sugar=(14/5) times (23/7)

total sugar=(14*23)/(5*7)

total sugar=322/35

total sugar=35/35+35/35+35/35+35/35+35/35+35/35+35/35+35/35+35/35+7/35

total sugar=1+1+1+1+1+1+1+1+1+7/35

total sugar=9+7/35

total sugar=9+1/5

total sugar=9 1/5 tons

your answer is b ^w^ hope i

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.