Arectangle and a square have the same area. the length of the rectangle is seventy feet more than two times its width. the length of a side of the square is thirty feet. which of the following equations would you solve for the dimensions of the rectangle? a) 30^2 = x(2x + 70) b) 30x^2 = 2x + 70 c) 302 = 70x * w mph d) 30 + 30 = 70 + x * 2 mph e) 30 * 2 = 70x^2 f) 100 = x^2 + x

The area of the square = 30^2  ft^2

area of the rectangle = x * (2x + 70) ft^2 (where x = the width)  and these areas are equal. Therefore:-

30^2 = x(2x + 70)

Its A

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17