The length of a line segment is m. this segment is divided into: a) three equal parts; b) five equal parts. find the distance between the midpoints of the first and the last parts in each case. i need the correct answer tysm if you answer!

Consider the case where each part is of length 1. Then the midpoint of the first segment is at 1/2.

a) If there are 3 segments, the midpoint of the last segment is halfway between 2 and 3, at 2 1/2. The distance from the first midpoint to the last midpoint is ...

... 2 1/2 - 1/2 = 2 . . . . . that is, 2/3 of the total line length

When the line length is m, that is 2/3·m

b) If there are 5 segments, the midpoint of the last segment is halfway between 4 and 5, at 4 1/2. The distance from the first midpoint to the last midpoint is ...

... 4 1/2 - 1/2 = 4 . . . . . that is, 4/5 of the total line length

When the line length is m, that is 4/5·m

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

answer: options

step-by-step explanation: