Solve the equation by graphing -3x+1=-8

Treat this problem as one involving finding the point at which two lines intersect.  

One line would be y = -3x + 1; the other would be the horiz. line y = -8.

Whenever two lines intersect, the coefficients of the point of intersection satisfy both equations.  Thus, we set y = y, or, in this case, -3x + 1 = -8.

Subtracting 1 from both sides, we get -3x + 1 - 1 = -8 - 1, or

-3x = -9, or (after dividing both lines by -3)  x = 3.

We already know that the y-coordinate of the point of intersection / solution is y = -8, so we can write the solution as

(3, -8)

First, draw the horizontal line y = -8.

Next, draw the line y = -3x + 1.  Letting x = 0, we get y = 1, which means that the y-intercept is (0,1).  Place a black dot at (0,1).  Now, taking info from the slope (-3), find and place a black dot at the next point, as follows:

From your dot at (0,1), move 1 unit to the right and then 3 units down.  This point will be (1,-3).  Place a black dot there.

Draw a line through your two black dots.  You'll see that this line and the line y = -8 intersect at (3,-8).

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl