In δabc, m∠cab = 60° and ad is an angle bisector with d ∈ bc and ad = 8 ft. find the distances from d to the sides of the triangle. ft, ft

The distance from D to the closest point on either side will be ...

... (8 ft)·sin(60°/2) = 4 ft

Both distances are 4 ft.

It isn't really clear that you don't want the distance along line BC; rather, you want the direct shortest distance to the side. For that, sufficient information is given.

answer: it's d

step-by-step explanation:

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c