The sum of 5 consecutive integers is 110 what is the fourth number in this sequence?

Hello from MrBillDoesMath!

  23

Steps:

Let "n" be the smallest integer in the set of 5 consecutive integer. Then

n + (n+1) + (n+2) + (n+3) + (n+4) = 110.  

Simplifying gives

5n + (1 + 2 +3 +4) = 110    or

5n + 10 = 110.   Subtracting 10 from each side gives

5n= 110-10 = 100

So n =  20, and the fourth number in the (n+3) or 20+3 or 23

Regards, MrB

i wish i could u

step-by-step explanation:

i wish i could u

don't give

take it once

try and try and you will not

happy to

pls mark as brainliest