Evaluating a piece wise defined function

Given : if x belongs to the interval -2 ≤ x < 2 then h(x) = -(x - 1)² + 1

As x = -2 belongs to the interval -2 ≤ x < 2

⇒ h(-2) = -(-2 - 1)² + 1 = -(-3)² + 1 = -9 + 1 = -8

As x = 1 belongs to the interval -2 ≤ x < 2

⇒ h(1) = -(1 - 1)² + 1 = 0 + 1 = 1

Given if x is greater than or equal to 2 then h(x) =

As x = 3 is greater than 2

⇒ h(3) =

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step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.