Find all the zeroes of the equation. -3x^4 + 27x^2 + 1200 = 0i just want more of an explanation on how to get it .

replace x^2 with m and try to solve

-3 m^2 +27 m +1200 =0

factor out -3

-3(m^2 -9m-400)=0

-3 (m-25) (m+16) =0

using the zero product property

m-25 =0 m+16=0

m=25  m=-16

then substitute m=x^2 back in

x^2 = 25   x^2 = -16

x take the square root of each side

x = +- sqrt (25)   if you know complex number  x = +- sqrt (-16)

x = +-5      x = +- 4i

 +5, -5 , +4i, -4i

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

well what did you do it matters what you did : )

step-by-step explanation: