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Mathematics, 02.07.2019 11:30 Savageboyn

Solve these with the full explained answer and you will get brainliest and 50 but hurry

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Answers: 1

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Answer from: xXCoryxKenshinXx

ANSWER TO QUESTION 1

The given equation is

4x+10=-26

We add the additive inverse of which is to both sides of the equation to obtain,

4x+10+-10=-26+-10

This gives us,

4x+10-10=-26-10

4x+0=-36

This further simplifies to

4x=-36

We divide both sides to obtain,

x=-4

ANSWER TO QUESTION 2

Since we got as answer to question one, the next question to answer is

$\frac{x}{3}+10=15$

We add the additive inverse of which is to both sides to obtain,

$\frac{x}{3}+10+-10=15+-10$

This gives us,

$\frac{x}{3}+10-10=15-10$

This simplifies to

$\frac{x}{3}+0=5$

$\frac{x}{3}=5$

We now multiply both sides of the equation by to obtain,

$3\times \frac{x}{3}=5\times3$

This implies that,

x=15

ANSWER TO QUESTION 3

The next equation is 9-2x=35

We add the additive inverse of which is to both sides of the equation to obtain,

9+-9-2x=35+-9

This gives us,

9-9-2x=35-9

This simplifies to,

-2x=26

We multiply both sides by the reciprocal or the multiplicative inverse of to obtain,

$-2x\times (-\frac{1}{2})=26\times(-\frac{1}{2})$

This gives us,

x=-13

ANSWER TO QUESTION 4.

The next question is $\frac{2}{3}x+15=17$

We add the additive inverse of 15 to both sides of the equation to obtain,

$\frac{2}{3}x+15+-15=17+-15$

This evaluates to

$\frac{2}{3}x+0=17-15$

This implies that,

$\frac{2}{3}x=2$

We multiply both sides by the multiplicative inverse or the reciprocal of $\frac{2}{3}$

This implies that,

$x=2\times\frac{3}{2}$

x=3

ANSWER TO QUESTION 5

The next question to answer is -5x-10=10 .

We add the additive inverse of which is to both sides of the equation to obtain,

-5x-10+10=10+10

This gives us,

-5x=20

We through by to obtain,

x=-4

ANSWER TO QUESTION 6

$\frac{3}{4}x-9=27$

We add the additive inverse of which is to both sides of the equation to obtain,

$\frac{3}{4}x-9+9=27+9$

This simplifies to;

$\frac{3}{4}x=36$

We multiply both sides of the equation by the reciprocal of $\frac{3}{4}$ to obtain,

$\frac{3}{4}x \times \frac{4}{3}=36\times \frac{4}{3}$

$x=36\times \frac{4}{3}$

$x=12\times 4$

x=48

ANSWER TO QUESTION 7

The next question to answer is $\frac{1}{2}x+13=9$ .

We add the additive inverse of which is to both sides of the equation to obtain,

$\frac{1}{2}x+13+-13=9+-13$

This will evaluate to,

$\frac{1}{2}x=-4$

We now multiply both sides of the equation by to obtain,

$x=-4\times 2$

x=-8

ANSWER TO QUESTION 8

The last question to solve now is $\frac{x-7}{4}=-2$

We first of all multiply both sides of the equation by to obtain,

$\frac{x-7}{4} \times 4=-2\times 4$

This implies that,

x-7=-8

We now add the additive inverse of which is 7 to both sides of the equation to obtain,

x-7+7=-8+7

This implies that

x=-1

ansver

Answer from: Quest

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70

ansver

Answer from: Quest

answer: the answer is 127 degrees

Find the measure of the missing angle pls me plsssss

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