Select the best answer (choices are in blue) for each of the statements below. 1 pt each 1. the forces shown above are pushing/ pulling forces. 2. the forces on each side of the fish are working together/opposite forces. 3. the forces are equal/unequal. 4. the forces are balanced/unbalanced. 5. the team on the right/left will fall into the water. 6. the net force is 300n/500n.    questions 7, 8 and 9 answer the questions below. 7. fill in the blanks: the gravitational force between the objects depends on the of the objects and the between them. 1 pt per blank 8. is there a stronger gravitational force between you and earth or an elephant and earth? 1 pt 9. the mass of all the spheres below are the same. is the gravitational force greater between the red or blue spheres?

1. The forces shown above are PUSHING/ PULLING forces.  = Pulling forces

2. The forces on each side of the fish are WORKING TOGETHER/OPPOSITE forces. = opposite forces

3.  The forces are EQUAL/UNEQUAL. =  Unequal

4. The forces are BALANCED/UNBALANCED. = unbalanced

5. The team on the RIGHT/LEFT will fall into the water. = right

6.  A net force is the sum of all forces acting on an object. So net force is 500N

7. The gravitational force between the objects depends on the MASS of the objects and the DISTANCE between them.

8.  The gravitational force is stronger between an elephant and Earth because the mass of the elephant is greater than your mass.

9. The gravitational force is greater between the blue spheres.

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!