Mathematics, 18.01.2020 10:31 nacmp890

If someone could answer these two questions, that would be wonderful:

1. describe how an ordered pair represents a point on a coordinate plane. include the terms x-coordinate, y-coordinate, and origin in your answer.

2. give the coordinates of one point in each of the four quadrants, one point on the x-axis, and one point on the y-axis

Answers: 2

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Answers

1. An ordered pair is a pair of numbers in parentheses, separated by a comma, which indicates the distance of a point from the origin. The first number represents the x-coordinate (where it is from side-to-side), and the second number represents the y-coordinate (where it is from up and down).

2. The four quadrants of the basic plane are listed in this order:

II | I
|

|
III | IV

A point in the first quadrant (I) could be (5, 10), since that means that you would be moving right 5 and up 10.

A point in the second quadrant (II) could be (-3, 6), since that means that you would be moving left 3 and up 6.

A point in the third quadrant (III) could be (-7, -1) since that means that you would be moving left 7 and down 1.

A point in the fourth quadrant (IV) could be (2, -6) since that means that you would be moving right 2 and down 6.

A point on the x-axis could be (9, 0) since that means that we are moving right 9 and making no vertical movement.

A point on the y-axis could be (0, 4), since that means that we are going up 4 and making no horizontal movement.

Hope that helped! =)

Answer from: Quest

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

hope to and hope that my answer is brainliest.(follow me )

Answer from: Quest

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

$x^2-2x+y^2-6y=26$

we now create space between the x and y terms with parenthesis.

$(x^2-2x)+(y^2-6y)=26$

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

$\frac{-2}{2} =(-1)^{2} =1$

$\frac{-6}{2} =(-3)^{2} =9$

we add the squares to both sides.

$(x^2-2x+1)+(y^2-6y+9)=26+1+9$

simplify.

$(x^2-2x+1)+(y^2-6y+9)=36$

and write the quadratics in factored form.

$(x-1)^{2} +(y-3)^{2} =36$

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

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If someone could answer these two questions, that would be wonderful:

1. describe how a...