You have two rectangles, rectangle abcd and efgh. the length of ab is x meters. the length of cd is 12 meters. the length of ef is 16 meters. the length of fg is x - 2 meters. you want to find the value of x so that the rectangles have the same area.

Let the area of the rectangle ABCD be denoted by .

Therefore, ........(Equation 1) [Reason: Area of any rectangle is the product of it's length and breadth]

Likewise, let the area of the rectangle EFGH be denoted by

Therefore, ....(Equation 2) [Reason: Area of any rectangle is the product of it's length and breadth]

Since the area of the two rectangles are equal, we will have:

Therefore, equating the two equations (Equation 1 and Equation 2) we get:

Thus, the value of x such that the rectangles have the same area is 8 meters.

4th option is correct xy=-10

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the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1