How do you do complete the square with circle in center radius form

we know that formula of circle in standard form

where

(h,k) is center of circle

r is radius of circle

Here , we can see that (x-h)^2 and (y-k)^2 are perfect squares

so, we will change our equations in perfect square

For example:

Firstly, we will change x terms into perfect square

step-1:

we will move constant term on right side

step-2:

We will move all x terms altogether

step-3:

Break x terms as 2*a*b

step-4:

now, we can use formula

we will identify b

so, we get b=8

to make 8^2 , we will add both sides by 8^2

now, we can write in perfect square form

step-5:

now, we can break y terms in 2ab form

step-6:

now, we can use formula

we will identify b

so, we get b=7

to make 7^2 , we will add both sides by 7^2

we can see that this is in standard equation of circle form

so, center=(-8,7)

radius=8

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

b). 4320 have a nice day