Which congruency theorem can be used to prove that △abd ≅ △dca? sss asa sas aas

SAS

Step-by-step explanation:

Given: Two triangles ΔABD and ΔDCA,

We have, AD=AD (common)

               ∠A=∠A (Given)

                BA=CD (Sides opposite to equal angles are always equal)

With the SAS rule of congruency,

ΔABD≅ΔDCA

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

step-by-step explanation:

your answer is a