Assume that when adults with smartphones are randomly selected, 46% use them in meetings or classes. if 6 adult smartphone users are randomly selected, find the probability that at least 3 of them use their smartphones in meetings or classes.

The probability is 0.1253.

This is binomial because 1) there are two outcomes (either do or do not use in class); 2) the events are independent of each other (the probability of one person using a phone in class does not affect the probability of another person doing this); and 3) there is a fixed number of trials (9).

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y= -2x+4, have a great day

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .