Ineed an equation of the line that passes through the given point and is parallel to the given line (6,-3); y=-2/3 x+5

y = -2/3 x + 1

Step-by-step explanation:

The line y = -2/3 x + 5 is in y = mx + b form, where m is the slope, so the slope of the given line is -2/3. Parallel lines have equal slopes, so the equation you are looking for also has slope -2/3.

The parallel line has equation

y = -2/3 x + b

We need to find b.

Since we are given a point, we substitute x and y with the x- and y-coordinates of the given point and solve for b. x = 6, and y = -3.

y = -2/3 x + b

-3 = (-2/3)(6) + b

-3 = -4 + b

1 = b

Now that we know b = 1, we can write the equation.

y = -2/3 x + b

y = -2/3 x + 1

if you was gonna solve for a, a is a   < -12

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.