The cost of 12 oranges and 6 apples is $5.38 eight oranges and 5 apples cost $3.68 find the cost of each

Let the oranges cost = x

Let the apples cost = y

According to given conditions, equation becomes:

.... (1)

   .....(2)

Multiplying equation (1) by 8 and equation (2) by 12 to get y

96x+48y=43.04   .... (3)

96x+60y=44.16 .... (4)

Now subtracting both equations we get,

12y = 1.12

y = 0.093

Hence, cost of 1 apple = $0.093

As 12x+6y=5.38

12x+6(0.093)=5.38

12x=4.822

x = 0.40

Hence, cost of 1 orange = $0.40

; )

step-by-step explanation: ; )

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b