Mathematics, 02.07.2019 23:30 Peterson6164
The circle below is centered at the point (2,-1) and has a radius of length 3. what is iis equation?
Answers: 1
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{2}{ h},\stackrel{-1}{ k})\qquad \qquad radius=\stackrel{3}{ r}\\[2em] [x-2]^2+[y-(-1)]^2=3^2\implies (x-2)^2+(y+1)^2=9](/tpl/images/0044/3180/cfebe.png)
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The circle below is centered at the point (2,-1) and has a radius of length 3. what is iis equation?...
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