Describe and correct the error to solving the equation. a there is an extraneous solution of  x=−4x=−4, so the solution is  x=5x=5.b there is an extraneous solution of  x=5x=5, so the solution is  x=−4x=−4.cthe absolute value cannot be negative, so there is no solution. d the absolute value cannot be negative, so one solution must be extraneous.

Given the system of equations presented here: 2x + 4y = 14 4x + y = 20 which of the following actions creates an equivalent system such that, when combined with the other equation, one of the variables is eliminated? multiply the second equation by â’4 to get â’16x â’ 4y = â’80 multiply the second equation by â’1 to get â’4x â’ y = â’20 multiply the first equation by 2 to get 4x + 8y = 28 multiply the first equation by â’1 to get â’2x â’ 4y = â’14